-3-7(x+2)=-8(1+x)-8x

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Solution for -3-7(x+2)=-8(1+x)-8x equation: 



-3-7(x+2)=-8(1+x)-8x

We move all terms to the left:

-3-7(x+2)-(-8(1+x)-8x)=0

We add all the numbers together, and all the variables

-7(x+2)-(-8(x+1)-8x)-3=0

We multiply parentheses

-7x-(-8(x+1)-8x)-14-3=0



We calculate terms in parentheses: -(-8(x+1)-8x), so:

-8(x+1)-8x

We add all the numbers together, and all the variables

-8x-8(x+1)

We multiply parentheses

-8x-8x-8

We add all the numbers together, and all the variables

-16x-8

Back to the equation:

-(-16x-8)



We add all the numbers together, and all the variables

-7x-(-16x-8)-17=0

We get rid of parentheses

-7x+16x+8-17=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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