-3-9+7j=6(3j-2)

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Solution for -3-9+7j=6(3j-2) equation: 



-3-9+7j=6(3j-2)

We move all terms to the left:

-3-9+7j-(6(3j-2))=0

We add all the numbers together, and all the variables

7j-(6(3j-2))-12=0



We calculate terms in parentheses: -(6(3j-2)), so:

6(3j-2)

We multiply parentheses

18j-12

Back to the equation:

-(18j-12)



We get rid of parentheses

7j-18j+12-12=0

We add all the numbers together, and all the variables

-11j=0

j=0/-11

j=0

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