-3.5x-7/10x+1/2x=56

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Solution for -3.5x-7/10x+1/2x=56 equation: 



-3.5x-7/10x+1/2x=56

We move all terms to the left:

-3.5x-7/10x+1/2x-(56)=0



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R





Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We calculate fractions


-3.5x+(-14x)/20x^2+10x/20x^2-56=0

We multiply all the terms by the denominator


-(3.5x)*20x^2+(-14x)+10x-56*20x^2=0

We add all the numbers together, and all the variables

-(+3.5x)*20x^2+(-14x)+10x-56*20x^2=0

We add all the numbers together, and all the variables

10x-(+3.5x)*20x^2+(-14x)-56*20x^2=0

Wy multiply elements

-1120x^2+10x-(+3.5x)*20x^2+(-14x)=0

We get rid of parentheses

-1120x^2+10x-(+3.5x)*20x^2-14x=0

We add all the numbers together, and all the variables

-1120x^2-4x-(+3.5x)*20x^2=0

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