-3.84=-0.04x(x+10)

Solution for -3.84=-0.04x(x+10) equation:

-3.84=-0.04x(x+10)

We move all terms to the left:

-3.84-(-0.04x(x+10))=0


We calculate terms in parentheses: -(-0.04x(x+10)), so:

-0.04x(x+10)

We multiply parentheses

-0x^2-0x

We add all the numbers together, and all the variables

-1x^2-1x

Back to the equation:

-(-1x^2-1x)


We get rid of parentheses

1x^2+1x-3.84=0

We add all the numbers together, and all the variables

x^2+x-3.84=0

a = 1; b = 1; c = -3.84;
Δ = b2-4ac
Δ = 12-4·1·(-3.84)
Δ = 16.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{16.36}}{2*1}=\frac{-1-\sqrt{16.36}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{16.36}}{2*1}=\frac{-1+\sqrt{16.36}}{2}
$