-3/(2v-4)+2=-8/(v-2)

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Solution for -3/(2v-4)+2=-8/(v-2) equation: 


D( v )

2*v-4 = 0

v-2 = 0

2*v-4 = 0

2*v-4 = 0

2*v-4 = 0 // + 4

2*v = 4 // : 2

v = 4/2

v = 2

v-2 = 0

v-2 = 0

v-2 = 0 // + 2

v = 2

v in (-oo:2) U (2:+oo)

2-3/(2*v-4) = -8/(v-2) // + -8/(v-2)

2-3/(2*v-4)-(-8/(v-2)) = 0

8*(v-2)^-1-3/(2*v-4)+2 = 0

8/(v-2)-3/(2*v-4)+2 = 0

(-3*(v-2))/((2*v-4)*(v-2))+(8*(2*v-4))/((2*v-4)*(v-2))+(2*(2*v-4)*(v-2))/((2*v-4)*(v-2)) = 0

8*(2*v-4)-3*(v-2)+2*(2*v-4)*(v-2) = 0

4*v^2+13*v-16*v-26+16 = 0

4*v^2-3*v-10 = 0

4*v^2-3*v-10 = 0

4*v^2-3*v-10 = 0

DELTA = (-3)^2-(-10*4*4)

DELTA = 169

DELTA > 0

v = (169^(1/2)+3)/(2*4) or v = (3-169^(1/2))/(2*4)

v = 2 or v = -5/4

(v+5/4)*(v-2) = 0

((v+5/4)*(v-2))/((2*v-4)*(v-2)) = 0

((v+5/4)*(v-2))/((2*v-4)*(v-2)) = 0 // * (2*v-4)*(v-2)

(v+5/4)*(v-2) = 0

( v+5/4 )

v+5/4 = 0 // - 5/4

v = -5/4

( v-2 )

v-2 = 0 // + 2

v = 2

v in { 2} 

v = -5/4

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