-3/10(x-200)=-1/2x+1/5(x+50)

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Solution for -3/10(x-200)=-1/2x+1/5(x+50) equation: 


x in (-oo:+oo)

(-3/10)*(x-200) = (1/5)*(x+50)+(-1/2)*x // - (1/5)*(x+50)+(-1/2)*x

(-3/10)*(x-200)-((1/5)*(x+50))-((-1/2)*x) = 0

(-3/10)*(x-200)+(-1/5)*(x+50)+(1/2)*x = 0

x/2-3/10*(x-200)-1/5*(x+50) = 0

(-3/10*2*(x-200))/2+(-1/5*2*(x+50))/2+x/2 = 0

x-3/10*2*(x-200)-1/5*2*(x+50) = 0

x-x+100 = 0

100 = 0

100/2 = 0

100/2 = 0 // * 2

100 = 0

x belongs to the empty set

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