-3/2(-6m-8)=7+4m

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Solution for -3/2(-6m-8)=7+4m equation: 



-3/2(-6m-8)=7+4m

We move all terms to the left:

-3/2(-6m-8)-(7+4m)=0



Domain of the equation: 2(-6m-8)!=0

m∈R



We add all the numbers together, and all the variables

-3/2(-6m-8)-(4m+7)=0

We get rid of parentheses

-3/2(-6m-8)-4m-7=0

We multiply all the terms by the denominator


-4m*2(-6m-8)-7*2(-6m-8)-3=0

Wy multiply elements

-8m^2(--14m(--3=0

We use the square of the difference formula

-8m^2(+14m(+3=0

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