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-3/2(12-6x)=2+2/3(6-9x)
We move all terms to the left:
-3/2(12-6x)-(2+2/3(6-9x))=0
Domain of the equation: 2(12-6x)!=0
x∈R
Domain of the equation: 3(6-9x))!=0We add all the numbers together, and all the variables
x∈R
-3/2(-6x+12)-(2+2/3(-9x+6))=0
We calculate fractions
(-9x(-)/(2(-6x+12)*3(-9x+6)))+(-4x0/(2(-6x+12)*3(-9x+6)))=0
We calculate terms in parentheses: +(-9x(-)/(2(-6x+12)*3(-9x+6))), so:
-9x(-)/(2(-6x+12)*3(-9x+6))
We add all the numbers together, and all the variables
-9x0/(2(-6x+12)*3(-9x+6))
We multiply all the terms by the denominator
-9x0
We add all the numbers together, and all the variables
-9x
Back to the equation:
+(-9x)
We calculate terms in parentheses: +(-4x0/(2(-6x+12)*3(-9x+6))), so:We get rid of parentheses
-4x0/(2(-6x+12)*3(-9x+6))
We multiply all the terms by the denominator
-4x0
We add all the numbers together, and all the variables
-4x
Back to the equation:
+(-4x)
-9x-4x=0
We add all the numbers together, and all the variables
-13x=0
x=0/-13
x=0
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