-3/2(p-2)-2=2-2/5(2p+5)

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Solution for -3/2(p-2)-2=2-2/5(2p+5) equation: 



-3/2(p-2)-2=2-2/5(2p+5)

We move all terms to the left:

-3/2(p-2)-2-(2-2/5(2p+5))=0



Domain of the equation: 2(p-2)!=0

p∈R





Domain of the equation: 5(2p+5))!=0

p∈R



We calculate fractions


(-15p2/(2(p-2)*5(2p+5)))+(-(-4pp)/(2(p-2)*5(2p+5)))-2=0



We calculate terms in parentheses: +(-15p2/(2(p-2)*5(2p+5))), so:

-15p2/(2(p-2)*5(2p+5))

We multiply all the terms by the denominator


-15p2

We add all the numbers together, and all the variables

-15p^2

Back to the equation:

+(-15p^2)





We calculate terms in parentheses: +(-(-4pp)/(2(p-2)*5(2p+5))), so:

-(-4pp)/(2(p-2)*5(2p+5))

We multiply all the terms by the denominator


-(-4pp)

We get rid of parentheses

4pp

Back to the equation:

+(4pp)



We get rid of parentheses

-15p^2+4pp-2=0

We move all terms containing p to the left, all other terms to the right

-15p^2+4pp=2

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