-3/2(x+2)=1/6(x+6)

Solution for -3/2(x+2)=1/6(x+6) equation:

-3/2(x+2)=1/6(x+6)

We move all terms to the left:

-3/2(x+2)-(1/6(x+6))=0


Domain of the equation: 2(x+2)!=0

x∈R



Domain of the equation: 6(x+6))!=0

x∈R


We calculate fractions


(-18xx/(2(x+2)*6(x+6)))+(-2xx/(2(x+2)*6(x+6)))=0


We calculate terms in parentheses: +(-18xx/(2(x+2)*6(x+6))), so:

-18xx/(2(x+2)*6(x+6))

We multiply all the terms by the denominator


-18xx

Back to the equation:

+(-18xx)



We calculate terms in parentheses: +(-2xx/(2(x+2)*6(x+6))), so:

-2xx/(2(x+2)*6(x+6))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

-18xx-2xx=0