-3/2(x-10)+5x=(2x-20)+11

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Solution for -3/2(x-10)+5x=(2x-20)+11 equation: 



-3/2(x-10)+5x=(2x-20)+11

We move all terms to the left:

-3/2(x-10)+5x-((2x-20)+11)=0



Domain of the equation: 2(x-10)!=0

x∈R



We add all the numbers together, and all the variables

5x-3/2(x-10)-((2x-20)+11)=0

We multiply all the terms by the denominator


5x*2(x-10)-(((2x-20)+11))*2(x-10)-3=0



We calculate terms in parentheses: -(((2x-20)+11))*2(x-10), so:

((2x-20)+11))*2(x-10



Wy multiply elements

10x^2(x-(((2x-20)+11))*2(x-10)-3=0

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