-3/20+3/2r=1/5r+r

Solution for -3/20+3/2r=1/5r+r equation:

-3/20+3/2r=1/5r+r

We move all terms to the left:

-3/20+3/2r-(1/5r+r)=0


Domain of the equation: 2r!=0

r!=0/2

r!=0

r∈R



Domain of the equation: 5r+r)!=0

r∈R


We add all the numbers together, and all the variables

3/2r-(+r+1/5r)-3/20=0

We get rid of parentheses

3/2r-r-1/5r-3/20=0

We calculate fractions


(-150r^2)/400r^2-r+600r/400r^2+(-80r)/400r^2=0

We add all the numbers together, and all the variables

(-150r^2)/400r^2-1r+600r/400r^2+(-80r)/400r^2=0

We multiply all the terms by the denominator


(-150r^2)-1r*400r^2+600r+(-80r)=0

We add all the numbers together, and all the variables

(-150r^2)+600r-1r*400r^2+(-80r)=0

Wy multiply elements

(-150r^2)-400r^3+600r+(-80r)=0

We get rid of parentheses

-150r^2-400r^3+600r-80r=0

We do not support erpression: r^3