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-3/2n+5/4n=-1/5
We move all terms to the left:
-3/2n+5/4n-(-1/5)=0
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
Domain of the equation: 4n!=0We get rid of parentheses
n!=0/4
n!=0
n∈R
-3/2n+5/4n+1/5=0
We calculate fractions
32n^2/200n^2+(-300n)/200n^2+250n/200n^2=0
We multiply all the terms by the denominator
32n^2+(-300n)+250n=0
We add all the numbers together, and all the variables
32n^2+250n+(-300n)=0
We get rid of parentheses
32n^2+250n-300n=0
We add all the numbers together, and all the variables
32n^2-50n=0
a = 32; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·32·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*32}=\frac{0}{64} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*32}=\frac{100}{64} =1+9/16 $
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