-3/2y-1/4y=7

Solution for -3/2y-1/4y=7 equation:

-3/2y-1/4y=7

We move all terms to the left:

-3/2y-1/4y-(7)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We calculate fractions


(-12y)/8y^2+(-2y)/8y^2-7=0

We multiply all the terms by the denominator


(-12y)+(-2y)-7*8y^2=0

Wy multiply elements

-56y^2+(-12y)+(-2y)=0

We get rid of parentheses

-56y^2-12y-2y=0

We add all the numbers together, and all the variables

-56y^2-14y=0

a = -56; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-56)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-56}=\frac{0}{-112}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-56}=\frac{28}{-112}
=-1/4
$