-3/4(-x+50)-6=0.4(3x+20)

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Solution for -3/4(-x+50)-6=0.4(3x+20) equation: 



-3/4(-x+50)-6=0.4(3x+20)

We move all terms to the left:

-3/4(-x+50)-6-(0.4(3x+20))=0



Domain of the equation: 4(-x+50)!=0

x∈R



We add all the numbers together, and all the variables

-3/4(-1x+50)-(0.4(3x+20))-6=0

We multiply all the terms by the denominator


-((0.4(3x+20)))*4(-1x+50)-6*4(-1x+50)-3=0



We calculate terms in parentheses: -((0.4(3x+20)))*4(-1x+50), so:

(0.4(3x+20)))*4(-1x+50

We add all the numbers together, and all the variables

-1x+(0.4(3x+20)))*4(+50

Back to the equation:

-(-1x+(0.4(3x+20)))*4(+50)



We add all the numbers together, and all the variables

-(-1x+(0.4(3x+20)))*450-6*4(-1x+50)-3=0

Wy multiply elements

-(-1x+(0.4(3x+20)))*450-24x(--3=0

We use the square of the difference formula

-(-1x+(0.4(3x+20)))*450-24x(+3=0

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