-3/4(4c-4)+7/8c=31/16

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Solution for -3/4(4c-4)+7/8c=31/16 equation: 



-3/4(4c-4)+7/8c=31/16

We move all terms to the left:

-3/4(4c-4)+7/8c-(31/16)=0



Domain of the equation: 4(4c-4)!=0

c∈R





Domain of the equation: 8c!=0

c!=0/8

c!=0

c∈R



We add all the numbers together, and all the variables

-3/4(4c-4)+7/8c-(+31/16)=0

We get rid of parentheses

-3/4(4c-4)+7/8c-31/16=0

We calculate fractions


(448c4/(4(4c-4)*8c*16)+(-992c^24/(4(4c-4)*8c*16)+(-384c)/(4(4c-4)*8c*16)=0



We calculate terms in parentheses: +(448c4/(4(4c-4)*8c*16)+(-992c^24/(4(4c-4)*8c*16)+(-384c)/(4(4c-4)*8c*16), so:

448c4/(4(4c-4)*8c*16)+(-992c^24/(4(4c-4)*8c*16)+(-384c)/(4(4c-4)*8c*16

We do not support ecpression: c^24

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