-3/4(7z-4)=1/4(4+3z)

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Solution for -3/4(7z-4)=1/4(4+3z) equation: 



-3/4(7z-4)=1/4(4+3z)

We move all terms to the left:

-3/4(7z-4)-(1/4(4+3z))=0



Domain of the equation: 4(7z-4)!=0

z∈R





Domain of the equation: 4(4+3z))!=0

z∈R



We add all the numbers together, and all the variables

-3/4(7z-4)-(1/4(3z+4))=0

We calculate fractions


(-12z3/(4(7z-4)*4(3z+4)))+(-4z7/(4(7z-4)*4(3z+4)))=0



We calculate terms in parentheses: +(-12z3/(4(7z-4)*4(3z+4))), so:

-12z3/(4(7z-4)*4(3z+4))

We multiply all the terms by the denominator


-12z3

We add all the numbers together, and all the variables

-12z^3

We do not support ezpression: z^3

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