-3/4(y+4)+3(y-10)=-6(y-4)+15

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Solution for -3/4(y+4)+3(y-10)=-6(y-4)+15 equation: 



-3/4(y+4)+3(y-10)=-6(y-4)+15

We move all terms to the left:

-3/4(y+4)+3(y-10)-(-6(y-4)+15)=0



Domain of the equation: 4(y+4)!=0

y∈R



We multiply parentheses

-3/4(y+4)+3y-(-6(y-4)+15)-30=0

We multiply all the terms by the denominator


3y*4(y+4)-((-6(y-4)+15))*4(y+4)-30*4(y+4)-3=0



We calculate terms in parentheses: -((-6(y-4)+15))*4(y+4), so:

(-6(y-4)+15))*4(y+4



Wy multiply elements

12y^2(y-((-6(y-4)+15))*4(y+4)-120y(y-3=0

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