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-3/4x-4=5+2x
We move all terms to the left:
-3/4x-4-(5+2x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-3/4x-(2x+5)-4=0
We get rid of parentheses
-3/4x-2x-5-4=0
We multiply all the terms by the denominator
-2x*4x-5*4x-4*4x-3=0
Wy multiply elements
-8x^2-20x-16x-3=0
We add all the numbers together, and all the variables
-8x^2-36x-3=0
a = -8; b = -36; c = -3;
Δ = b2-4ac
Δ = -362-4·(-8)·(-3)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-20\sqrt{3}}{2*-8}=\frac{36-20\sqrt{3}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+20\sqrt{3}}{2*-8}=\frac{36+20\sqrt{3}}{-16} $
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