-3/4b+3=12

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Solution for -3/4b+3=12 equation: 



-3/4b+3=12

We move all terms to the left:

-3/4b+3-(12)=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



We add all the numbers together, and all the variables

-3/4b-9=0

We multiply all the terms by the denominator


-9*4b-3=0

Wy multiply elements

-36b-3=0

We move all terms containing b to the left, all other terms to the right

-36b=3

b=3/-36

b=-1/12

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