-3/4j-2+1/2j=3/2-j

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Solution for -3/4j-2+1/2j=3/2-j equation: 



-3/4j-2+1/2j=3/2-j

We move all terms to the left:

-3/4j-2+1/2j-(3/2-j)=0



Domain of the equation: 4j!=0

j!=0/4

j!=0

j∈R





Domain of the equation: 2j!=0

j!=0/2

j!=0

j∈R





Domain of the equation: 2-j)!=0

We move all terms containing j to the left, all other terms to the right

-j)!=-2

j!=-2/1

j!=-2

j∈R



We add all the numbers together, and all the variables

-3/4j+1/2j-(-1j+3/2)-2=0

We get rid of parentheses

-3/4j+1/2j+1j-2-3/2=0

We calculate fractions


1j+(-24j)/32j^2+4j/32j^2+(-12j)/32j^2-2=0

We add all the numbers together, and all the variables

j+(-24j)/32j^2+4j/32j^2+(-12j)/32j^2-2=0

We multiply all the terms by the denominator


j*32j^2+(-24j)+4j+(-12j)-2*32j^2=0

We add all the numbers together, and all the variables

4j+j*32j^2+(-24j)+(-12j)-2*32j^2=0

Wy multiply elements

32j^3-64j^2+4j+(-24j)+(-12j)=0

We get rid of parentheses

32j^3-64j^2+4j-24j-12j=0

We do not support ejpression: j^3

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