-3/4m-1/2=2+1/2m

Solution for -3/4m-1/2=2+1/2m equation:

-3/4m-1/2=2+1/2m

We move all terms to the left:

-3/4m-1/2-(2+1/2m)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 2m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

-3/4m-(1/2m+2)-1/2=0

We get rid of parentheses

-3/4m-1/2m-2-1/2=0

We calculate fractions


(-24m)/32m^2+(-4m)/32m^2+(-4m)/32m^2-2=0

We multiply all the terms by the denominator


(-24m)+(-4m)+(-4m)-2*32m^2=0

Wy multiply elements

-64m^2+(-24m)+(-4m)+(-4m)=0

We get rid of parentheses

-64m^2-24m-4m-4m=0

We add all the numbers together, and all the variables

-64m^2-32m=0

a = -64; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·(-64)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*-64}=\frac{0}{-128}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*-64}=\frac{64}{-128}
=-1/2
$