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-3/4x-8=-x+4
We move all terms to the left:
-3/4x-8-(-x+4)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-3/4x-(-1x+4)-8=0
We get rid of parentheses
-3/4x+1x-4-8=0
We multiply all the terms by the denominator
1x*4x-4*4x-8*4x-3=0
Wy multiply elements
4x^2-16x-32x-3=0
We add all the numbers together, and all the variables
4x^2-48x-3=0
a = 4; b = -48; c = -3;
Δ = b2-4ac
Δ = -482-4·4·(-3)
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-28\sqrt{3}}{2*4}=\frac{48-28\sqrt{3}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+28\sqrt{3}}{2*4}=\frac{48+28\sqrt{3}}{8} $
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