-3/4z+1=16

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Solution for -3/4z+1=16 equation: 



-3/4z+1=16

We move all terms to the left:

-3/4z+1-(16)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

-3/4z-15=0

We multiply all the terms by the denominator


-15*4z-3=0

Wy multiply elements

-60z-3=0

We move all terms containing z to the left, all other terms to the right

-60z=3

z=3/-60

z=-1/20

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