-3/5(2x-5)=-2/3(x+3)

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Solution for -3/5(2x-5)=-2/3(x+3) equation: 



-3/5(2x-5)=-2/3(x+3)

We move all terms to the left:

-3/5(2x-5)-(-2/3(x+3))=0



Domain of the equation: 5(2x-5)!=0

x∈R





Domain of the equation: 3(x+3))!=0

x∈R



We calculate fractions


(-9xx/(5(2x-5)*3(x+3)))+(-(-10x2)/(5(2x-5)*3(x+3)))=0



We calculate terms in parentheses: +(-9xx/(5(2x-5)*3(x+3))), so:

-9xx/(5(2x-5)*3(x+3))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)





We calculate terms in parentheses: +(-(-10x2)/(5(2x-5)*3(x+3))), so:

-(-10x2)/(5(2x-5)*3(x+3))

We add all the numbers together, and all the variables

-(-10x^2)/(5(2x-5)*3(x+3))

We multiply all the terms by the denominator


-(-10x^2)

We get rid of parentheses

10x^2

Back to the equation:

+(10x^2)



determiningTheFunctionDomain
10x^2+(-9xx)=0

We get rid of parentheses

10x^2-9xx=0

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