-3/5(8y+2)-5/10(-7y-3)=-18/5

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Solution for -3/5(8y+2)-5/10(-7y-3)=-18/5 equation: 



-3/5(8y+2)-5/10(-7y-3)=-18/5

We move all terms to the left:

-3/5(8y+2)-5/10(-7y-3)-(-18/5)=0



Domain of the equation: 5(8y+2)!=0

y∈R





Domain of the equation: 10(-7y-3)!=0

y∈R



We get rid of parentheses

-3/5(8y+2)-5/10(-7y-3)+18/5=0

We calculate fractions


(-30y(-)/(5(8y+2)*10(-7y-3)*5)+(-125y8/(5(8y+2)*10(-7y-3)*5)+(180y(-)/(5(8y+2)*10(-7y-3)*5)=0



We calculate terms in parentheses: +(-30y(-)/(5(8y+2)*10(-7y-3)*5)+(-125y8/(5(8y+2)*10(-7y-3)*5)+(180y(-)/(5(8y+2)*10(-7y-3)*5), so:

-30y(-)/(5(8y+2)*10(-7y-3)*5)+(-125y8/(5(8y+2)*10(-7y-3)*5)+(180y(-)/(5(8y+2)*10(-7y-3)*5

We can not solve this equation

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