-3/5b+41=-22

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Solution for -3/5b+41=-22 equation: 



-3/5b+41=-22

We move all terms to the left:

-3/5b+41-(-22)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

-3/5b+63=0

We multiply all the terms by the denominator


63*5b-3=0

Wy multiply elements

315b-3=0

We move all terms containing b to the left, all other terms to the right

315b=3

b=3/315

b=1/105

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