-3/5b=+7+2/5b=19

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Solution for -3/5b=+7+2/5b=19 equation:



-3/5b=+7+2/5b=19
We move all terms to the left:
-3/5b-(+7+2/5b)=0
Domain of the equation: 5b!=0
b!=0/5
b!=0
b∈R
Domain of the equation: 5b)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
-3/5b-(2/5b+7)=0
We get rid of parentheses
-3/5b-2/5b-7=0
We multiply all the terms by the denominator
-7*5b-3-2=0
We add all the numbers together, and all the variables
-7*5b-5=0
Wy multiply elements
-35b-5=0
We move all terms containing b to the left, all other terms to the right
-35b=5
b=5/-35
b=-1/7

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