-3/5x+-7/10x=-56

Solution for -3/5x+-7/10x=-56 equation:

-3/5x+-7/10x=-56

We move all terms to the left:

-3/5x+-7/10x-(-56)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

-3/5x-7/10x+56=0

We calculate fractions


(-30x)/50x^2+(-35x)/50x^2+56=0

We multiply all the terms by the denominator


(-30x)+(-35x)+56*50x^2=0

Wy multiply elements

2800x^2+(-30x)+(-35x)=0

We get rid of parentheses

2800x^2-30x-35x=0

We add all the numbers together, and all the variables

2800x^2-65x=0

a = 2800; b = -65; c = 0;
Δ = b2-4ac
Δ = -652-4·2800·0
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-65}{2*2800}=\frac{0}{5600}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+65}{2*2800}=\frac{130}{5600}
=13/560
$