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-3/5x-7/10+1/4x=-56
We move all terms to the left:
-3/5x-7/10+1/4x-(-56)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-3/5x+1/4x+56-7/10=0
We calculate fractions
(-560x^2)/200x^2+(-120x)/200x^2+50x/200x^2+56=0
We multiply all the terms by the denominator
(-560x^2)+(-120x)+50x+56*200x^2=0
We add all the numbers together, and all the variables
(-560x^2)+50x+(-120x)+56*200x^2=0
Wy multiply elements
(-560x^2)+11200x^2+50x+(-120x)=0
We get rid of parentheses
-560x^2+11200x^2+50x-120x=0
We add all the numbers together, and all the variables
10640x^2-70x=0
a = 10640; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·10640·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*10640}=\frac{0}{21280} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*10640}=\frac{140}{21280} =1/152 $
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