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-3/5x-7/10x=1
We move all terms to the left:
-3/5x-7/10x-(1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x!=0We calculate fractions
x!=0/10
x!=0
x∈R
(-30x)/50x^2+(-35x)/50x^2-1=0
We multiply all the terms by the denominator
(-30x)+(-35x)-1*50x^2=0
Wy multiply elements
-50x^2+(-30x)+(-35x)=0
We get rid of parentheses
-50x^2-30x-35x=0
We add all the numbers together, and all the variables
-50x^2-65x=0
a = -50; b = -65; c = 0;
Δ = b2-4ac
Δ = -652-4·(-50)·0
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-65}{2*-50}=\frac{0}{-100} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+65}{2*-50}=\frac{130}{-100} =-1+3/10 $
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