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-3/5x=x+16
We move all terms to the left:
-3/5x-(x+16)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
-3/5x-x-16=0
We multiply all the terms by the denominator
-x*5x-16*5x-3=0
Wy multiply elements
-5x^2-80x-3=0
a = -5; b = -80; c = -3;
Δ = b2-4ac
Δ = -802-4·(-5)·(-3)
Δ = 6340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6340}=\sqrt{4*1585}=\sqrt{4}*\sqrt{1585}=2\sqrt{1585}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1585}}{2*-5}=\frac{80-2\sqrt{1585}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1585}}{2*-5}=\frac{80+2\sqrt{1585}}{-10} $
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