-3/5y-1/7y=9/10

Solution for -3/5y-1/7y=9/10 equation:

-3/5y-1/7y=9/10

We move all terms to the left:

-3/5y-1/7y-(9/10)=0


Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R


We add all the numbers together, and all the variables

-3/5y-1/7y-(+9/10)=0

We get rid of parentheses

-3/5y-1/7y-9/10=0

We calculate fractions


(-2205y^2)/350y^2+(-210y)/350y^2+(-50y)/350y^2=0

We multiply all the terms by the denominator


(-2205y^2)+(-210y)+(-50y)=0

We get rid of parentheses

-2205y^2-210y-50y=0

We add all the numbers together, and all the variables

-2205y^2-260y=0

a = -2205; b = -260; c = 0;
Δ = b2-4ac
Δ = -2602-4·(-2205)·0
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-260}{2*-2205}=\frac{0}{-4410}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+260}{2*-2205}=\frac{520}{-4410}
=-52/441
$