-3/5y-7/19y=26

Solution for -3/5y-7/19y=26 equation:

-3/5y-7/19y=26

We move all terms to the left:

-3/5y-7/19y-(26)=0


Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



Domain of the equation: 19y!=0

y!=0/19

y!=0

y∈R


We calculate fractions


(-57y)/95y^2+(-35y)/95y^2-26=0

We multiply all the terms by the denominator


(-57y)+(-35y)-26*95y^2=0

Wy multiply elements

-2470y^2+(-57y)+(-35y)=0

We get rid of parentheses

-2470y^2-57y-35y=0

We add all the numbers together, and all the variables

-2470y^2-92y=0

a = -2470; b = -92; c = 0;
Δ = b2-4ac
Δ = -922-4·(-2470)·0
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-92}{2*-2470}=\frac{0}{-4940}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+92}{2*-2470}=\frac{184}{-4940}
=-46/1235
$