-3/8(-6-2y)=1/2(2-3)-1

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Solution for -3/8(-6-2y)=1/2(2-3)-1 equation: 



-3/8(-6-2y)=1/2(2-3)-1

We move all terms to the left:

-3/8(-6-2y)-(1/2(2-3)-1)=0



Domain of the equation: 8(-6-2y)!=0

y∈R



We add all the numbers together, and all the variables

-3/8(-2y-6)-(1/2(-1)-1)=0

We calculate fractions


()/(8(-2y-6)*2(-1))+(-8y0/(8(-2y-6)*2(-1))=0



We calculate terms in parentheses: +()/(8(-2y-6)*2(-1)), so:

)/(8(-2y-6)*2(-1)

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()





We calculate terms in parentheses: +(-8y0/(8(-2y-6)*2(-1)), so:

-8y0/(8(-2y-6)*2(-1)

We multiply all the terms by the denominator


-8y0

We add all the numbers together, and all the variables

-8y

Back to the equation:

+(-8y)



We add all the numbers together, and all the variables

(-8y)=0

We get rid of parentheses

-8y=0

y=0/-8

y=0

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