-3/x=(7/3x)-3

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Solution for -3/x=(7/3x)-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

-3/x = (7/3)*x-3 // - (7/3)*x-3

3-((7/3)*x)-3/x = 0

(-7/3)*x-3/x+3 = 0

3*x^0-7/3*x^1-3*x^-1 = 0

(3*x^1-7/3*x^2-3*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^1-7/3*x^2-3*x^0) = 0

x^1

(-7/3)*x^2+3*x-3 = 0

(-7/3)*x^2+3*x-3 = 0

DELTA = 3^2-(-3*4*(-7/3))

DELTA = -19

DELTA < 0

x in { } 

x belongs to the empty set

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