-30+6(3a+1)=3(2a-4)

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Solution for -30+6(3a+1)=3(2a-4) equation: 



-30+6(3a+1)=3(2a-4)

We move all terms to the left:

-30+6(3a+1)-(3(2a-4))=0

We multiply parentheses

18a-(3(2a-4))+6-30=0



We calculate terms in parentheses: -(3(2a-4)), so:

3(2a-4)

We multiply parentheses

6a-12

Back to the equation:

-(6a-12)



We add all the numbers together, and all the variables

18a-(6a-12)-24=0

We get rid of parentheses

18a-6a+12-24=0

We add all the numbers together, and all the variables

12a-12=0

We move all terms containing a to the left, all other terms to the right

12a=12

a=12/12

a=1

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