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-30=5(x+1)x
We move all terms to the left:
-30-(5(x+1)x)=0
We calculate terms in parentheses: -(5(x+1)x), so:We get rid of parentheses
5(x+1)x
We multiply parentheses
5x^2+5x
Back to the equation:
-(5x^2+5x)
-5x^2-5x-30=0
a = -5; b = -5; c = -30;
Δ = b2-4ac
Δ = -52-4·(-5)·(-30)
Δ = -575
Delta is less than zero, so there is no solution for the equation
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