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-30=x(x+13)
We move all terms to the left:
-30-(x(x+13))=0
We calculate terms in parentheses: -(x(x+13)), so:We get rid of parentheses
x(x+13)
We multiply parentheses
x^2+13x
Back to the equation:
-(x^2+13x)
-x^2-13x-30=0
We add all the numbers together, and all the variables
-1x^2-13x-30=0
a = -1; b = -13; c = -30;
Δ = b2-4ac
Δ = -132-4·(-1)·(-30)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-7}{2*-1}=\frac{6}{-2} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+7}{2*-1}=\frac{20}{-2} =-10 $
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