-312=8(1+4v)+v

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Solution for -312=8(1+4v)+v equation:



-312=8(1+4v)+v
We move all terms to the left:
-312-(8(1+4v)+v)=0
We add all the numbers together, and all the variables
-(8(4v+1)+v)-312=0
We calculate terms in parentheses: -(8(4v+1)+v), so:
8(4v+1)+v
We add all the numbers together, and all the variables
v+8(4v+1)
We multiply parentheses
v+32v+8
We add all the numbers together, and all the variables
33v+8
Back to the equation:
-(33v+8)
We get rid of parentheses
-33v-8-312=0
We add all the numbers together, and all the variables
-33v-320=0
We move all terms containing v to the left, all other terms to the right
-33v=320
v=320/-33
v=-9+23/33

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