-31x2-62x+93=0

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Solution for -31x2-62x+93=0 equation:



-31x^2-62x+93=0
a = -31; b = -62; c = +93;
Δ = b2-4ac
Δ = -622-4·(-31)·93
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-124}{2*-31}=\frac{-62}{-62} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+124}{2*-31}=\frac{186}{-62} =-3 $

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