-32+4=6z-3(3z+2)

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Solution for -32+4=6z-3(3z+2) equation: 



-32+4=6z-3(3z+2)

We move all terms to the left:

-32+4-(6z-3(3z+2))=0

We add all the numbers together, and all the variables

-(6z-3(3z+2))-28=0



We calculate terms in parentheses: -(6z-3(3z+2)), so:

6z-3(3z+2)

We multiply parentheses

6z-9z-6

We add all the numbers together, and all the variables

-3z-6

Back to the equation:

-(-3z-6)



We get rid of parentheses

3z+6-28=0

We add all the numbers together, and all the variables

3z-22=0

We move all terms containing z to the left, all other terms to the right

3z=22

z=22/3

z=7+1/3

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