-32+6f=2f+20

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Solution for -32+6f=2f+20 equation:



-32+6f=2f+20
We move all terms to the left:
-32+6f-(2f+20)=0
We get rid of parentheses
6f-2f-20-32=0
We add all the numbers together, and all the variables
4f-52=0
We move all terms containing f to the left, all other terms to the right
4f=52
f=52/4
f=13

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