-32+6f=2f+20

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Solution for -32+6f=2f+20 equation: 



-32+6f=2f+20

We move all terms to the left:

-32+6f-(2f+20)=0

We get rid of parentheses

6f-2f-20-32=0

We add all the numbers together, and all the variables

4f-52=0

We move all terms containing f to the left, all other terms to the right

4f=52

f=52/4

f=13

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