-32+8v=5(2+7v)-6v

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Solution for -32+8v=5(2+7v)-6v equation: 



-32+8v=5(2+7v)-6v

We move all terms to the left:

-32+8v-(5(2+7v)-6v)=0

We add all the numbers together, and all the variables

8v-(5(7v+2)-6v)-32=0



We calculate terms in parentheses: -(5(7v+2)-6v), so:

5(7v+2)-6v

We add all the numbers together, and all the variables

-6v+5(7v+2)

We multiply parentheses

-6v+35v+10

We add all the numbers together, and all the variables

29v+10

Back to the equation:

-(29v+10)



We get rid of parentheses

8v-29v-10-32=0

We add all the numbers together, and all the variables

-21v-42=0

We move all terms containing v to the left, all other terms to the right

-21v=42

v=42/-21

v=-2

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