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-32-(3)/(5)f=-17
We move all terms to the left:
-32-(3)/(5)f-(-17)=0
Domain of the equation: 5f!=0We add all the numbers together, and all the variables
f!=0/5
f!=0
f∈R
-3/5f-15=0
We multiply all the terms by the denominator
-15*5f-3=0
Wy multiply elements
-75f-3=0
We move all terms containing f to the left, all other terms to the right
-75f=3
f=3/-75
f=-1/25
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