-32-4a=5(-4-2a)

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Solution for -32-4a=5(-4-2a) equation: 



-32-4a=5(-4-2a)

We move all terms to the left:

-32-4a-(5(-4-2a))=0

We add all the numbers together, and all the variables

-4a-(5(-2a-4))-32=0



We calculate terms in parentheses: -(5(-2a-4)), so:

5(-2a-4)

We multiply parentheses

-10a-20

Back to the equation:

-(-10a-20)



We get rid of parentheses

-4a+10a+20-32=0

We add all the numbers together, and all the variables

6a-12=0

We move all terms containing a to the left, all other terms to the right

6a=12

a=12/6

a=2

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