-32-5v=-10-2(4v+5)

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Solution for -32-5v=-10-2(4v+5) equation: 



-32-5v=-10-2(4v+5)

We move all terms to the left:

-32-5v-(-10-2(4v+5))=0



We calculate terms in parentheses: -(-10-2(4v+5)), so:

-10-2(4v+5)

determiningTheFunctionDomain
-2(4v+5)-10

We multiply parentheses

-8v-10-10

We add all the numbers together, and all the variables

-8v-20

Back to the equation:

-(-8v-20)



We get rid of parentheses

-5v+8v+20-32=0

We add all the numbers together, and all the variables

3v-12=0

We move all terms containing v to the left, all other terms to the right

3v=12

v=12/3

v=4

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