-32-5v=6(-3v-2)-7v

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Solution for -32-5v=6(-3v-2)-7v equation: 



-32-5v=6(-3v-2)-7v

We move all terms to the left:

-32-5v-(6(-3v-2)-7v)=0



We calculate terms in parentheses: -(6(-3v-2)-7v), so:

6(-3v-2)-7v

We add all the numbers together, and all the variables

-7v+6(-3v-2)

We multiply parentheses

-7v-18v-12

We add all the numbers together, and all the variables

-25v-12

Back to the equation:

-(-25v-12)



We get rid of parentheses

-5v+25v+12-32=0

We add all the numbers together, and all the variables

20v-20=0

We move all terms containing v to the left, all other terms to the right

20v=20

v=20/20

v=1

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