-32-n=6(n-3)

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Solution for -32-n=6(n-3) equation: 



-32-n=6(n-3)

We move all terms to the left:

-32-n-(6(n-3))=0

We add all the numbers together, and all the variables

-1n-(6(n-3))-32=0



We calculate terms in parentheses: -(6(n-3)), so:

6(n-3)

We multiply parentheses

6n-18

Back to the equation:

-(6n-18)



We get rid of parentheses

-1n-6n+18-32=0

We add all the numbers together, and all the variables

-7n-14=0

We move all terms containing n to the left, all other terms to the right

-7n=14

n=14/-7

n=-2

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