If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(-32/12)/3 = 0
-8/3/3 = 0
-8/9 = 0
L <> R
| (3x+1)(3x^2+2x-1)= | | 3/5y-y=4+1/8y | | -1=-5+n+1 | | .15x=200+.02 | | x/2x+x/x=1 | | 2p+8=14 | | -8t+2=-5t-6t | | (2x^2+6x+10)+(4x^2+2x+3)=y | | 3g+5=1g+4 | | 5/8+m=3/4 | | 19-8.2= | | -8=-2(v+11) | | (x-4)(x^2-2x+3)= | | (2x^2+6x+10)+(4x^2+2x+3)=x | | p-3p=8 | | 5(2v+44)=170 | | 1.33(4x-3)=2.38x-1.59 | | -7/8*-52/5 | | -32-1/5b-2/5b=-17 | | 4y-16+8y=14 | | 8x-7=3x-7+5 | | (2x^2+6x+10)+(4x^2+2x+3)= | | 17=2-3(-2x+1)-10 | | 4y-6x=48 | | 1=(1/2)(4x+2) | | (4(2x+3)/5)-((x+1)/4)=31/5 | | 8(1+4h)= | | -7=k-4-2k | | 3x+(x-5)=215 | | 4(5c-1)-5=18c+3 | | 12x-(8+7x)= | | 8(1+4)= |